Integrand size = 35, antiderivative size = 200 \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a^{5/2} (163 A+304 C) \arctan \left (\frac {\sqrt {a} \tan (c+d x)}{\sqrt {a+a \sec (c+d x)}}\right )}{64 d}+\frac {a^3 (299 A+432 C) \sin (c+d x)}{192 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (17 A+16 C) \cos (c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{32 d}+\frac {5 a A \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \sin (c+d x)}{24 d}+\frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d} \]
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Time = 0.86 (sec) , antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {4172, 4102, 4100, 3859, 209} \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a^{5/2} (163 A+304 C) \arctan \left (\frac {\sqrt {a} \tan (c+d x)}{\sqrt {a \sec (c+d x)+a}}\right )}{64 d}+\frac {a^3 (299 A+432 C) \sin (c+d x)}{192 d \sqrt {a \sec (c+d x)+a}}+\frac {a^2 (17 A+16 C) \sin (c+d x) \cos (c+d x) \sqrt {a \sec (c+d x)+a}}{32 d}+\frac {A \sin (c+d x) \cos ^3(c+d x) (a \sec (c+d x)+a)^{5/2}}{4 d}+\frac {5 a A \sin (c+d x) \cos ^2(c+d x) (a \sec (c+d x)+a)^{3/2}}{24 d} \]
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Rule 209
Rule 3859
Rule 4100
Rule 4102
Rule 4172
Rubi steps \begin{align*} \text {integral}& = \frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d}+\frac {\int \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \left (\frac {5 a A}{2}+\frac {1}{2} a (A+8 C) \sec (c+d x)\right ) \, dx}{4 a} \\ & = \frac {5 a A \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \sin (c+d x)}{24 d}+\frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d}+\frac {\int \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \left (\frac {3}{4} a^2 (17 A+16 C)+\frac {1}{4} a^2 (11 A+48 C) \sec (c+d x)\right ) \, dx}{12 a} \\ & = \frac {a^2 (17 A+16 C) \cos (c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{32 d}+\frac {5 a A \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \sin (c+d x)}{24 d}+\frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d}+\frac {\int \cos (c+d x) \sqrt {a+a \sec (c+d x)} \left (\frac {1}{8} a^3 (299 A+432 C)+\frac {5}{8} a^3 (19 A+48 C) \sec (c+d x)\right ) \, dx}{24 a} \\ & = \frac {a^3 (299 A+432 C) \sin (c+d x)}{192 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (17 A+16 C) \cos (c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{32 d}+\frac {5 a A \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \sin (c+d x)}{24 d}+\frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d}+\frac {1}{128} \left (a^2 (163 A+304 C)\right ) \int \sqrt {a+a \sec (c+d x)} \, dx \\ & = \frac {a^3 (299 A+432 C) \sin (c+d x)}{192 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (17 A+16 C) \cos (c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{32 d}+\frac {5 a A \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \sin (c+d x)}{24 d}+\frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d}-\frac {\left (a^3 (163 A+304 C)\right ) \text {Subst}\left (\int \frac {1}{a+x^2} \, dx,x,-\frac {a \tan (c+d x)}{\sqrt {a+a \sec (c+d x)}}\right )}{64 d} \\ & = \frac {a^{5/2} (163 A+304 C) \arctan \left (\frac {\sqrt {a} \tan (c+d x)}{\sqrt {a+a \sec (c+d x)}}\right )}{64 d}+\frac {a^3 (299 A+432 C) \sin (c+d x)}{192 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (17 A+16 C) \cos (c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{32 d}+\frac {5 a A \cos ^2(c+d x) (a+a \sec (c+d x))^{3/2} \sin (c+d x)}{24 d}+\frac {A \cos ^3(c+d x) (a+a \sec (c+d x))^{5/2} \sin (c+d x)}{4 d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 3.16 (sec) , antiderivative size = 335, normalized size of antiderivative = 1.68 \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a^2 \left (675 A \text {arctanh}\left (\sqrt {1-\sec (c+d x)}\right )+560 C \text {arctanh}\left (\sqrt {1-\sec (c+d x)}\right )+231 A \sqrt {1-\sec (c+d x)}-240 C \sqrt {1-\sec (c+d x)}+849 A \cos (c+d x) \sqrt {1-\sec (c+d x)}-80 C \cos (c+d x) \sqrt {1-\sec (c+d x)}+233 A \cos (2 (c+d x)) \sqrt {1-\sec (c+d x)}-240 C \cos (2 (c+d x)) \sqrt {1-\sec (c+d x)}+58 A \cos (3 (c+d x)) \sqrt {1-\sec (c+d x)}+2 A \cos (4 (c+d x)) \sqrt {1-\sec (c+d x)}+2560 C \operatorname {Hypergeometric2F1}\left (\frac {1}{2},3,\frac {3}{2},1-\sec (c+d x)\right ) \sqrt {1-\sec (c+d x)}+512 A \operatorname {Hypergeometric2F1}\left (\frac {1}{2},5,\frac {3}{2},1-\sec (c+d x)\right ) \sqrt {1-\sec (c+d x)}\right ) \sqrt {a (1+\sec (c+d x))} \tan \left (\frac {1}{2} (c+d x)\right )}{320 d \sqrt {1-\sec (c+d x)}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(385\) vs. \(2(176)=352\).
Time = 0.32 (sec) , antiderivative size = 386, normalized size of antiderivative = 1.93
\[\frac {a^{2} \left (48 A \cos \left (d x +c \right )^{4} \sin \left (d x +c \right )+184 A \cos \left (d x +c \right )^{3} \sin \left (d x +c \right )+489 A \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \operatorname {arctanh}\left (\frac {\sin \left (d x +c \right )}{\left (\cos \left (d x +c \right )+1\right ) \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}}\right ) \cos \left (d x +c \right )+326 A \cos \left (d x +c \right )^{2} \sin \left (d x +c \right )+912 C \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \operatorname {arctanh}\left (\frac {\sin \left (d x +c \right )}{\left (\cos \left (d x +c \right )+1\right ) \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}}\right ) \cos \left (d x +c \right )+96 C \cos \left (d x +c \right )^{2} \sin \left (d x +c \right )+489 A \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \operatorname {arctanh}\left (\frac {\sin \left (d x +c \right )}{\left (\cos \left (d x +c \right )+1\right ) \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}}\right )+489 A \cos \left (d x +c \right ) \sin \left (d x +c \right )+912 C \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \operatorname {arctanh}\left (\frac {\sin \left (d x +c \right )}{\left (\cos \left (d x +c \right )+1\right ) \sqrt {-\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}}\right )+528 C \cos \left (d x +c \right ) \sin \left (d x +c \right )\right ) \sqrt {a \left (1+\sec \left (d x +c \right )\right )}}{192 d \left (\cos \left (d x +c \right )+1\right )}\]
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Time = 0.33 (sec) , antiderivative size = 408, normalized size of antiderivative = 2.04 \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\left [\frac {3 \, {\left ({\left (163 \, A + 304 \, C\right )} a^{2} \cos \left (d x + c\right ) + {\left (163 \, A + 304 \, C\right )} a^{2}\right )} \sqrt {-a} \log \left (\frac {2 \, a \cos \left (d x + c\right )^{2} - 2 \, \sqrt {-a} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + a \cos \left (d x + c\right ) - a}{\cos \left (d x + c\right ) + 1}\right ) + 2 \, {\left (48 \, A a^{2} \cos \left (d x + c\right )^{4} + 184 \, A a^{2} \cos \left (d x + c\right )^{3} + 2 \, {\left (163 \, A + 48 \, C\right )} a^{2} \cos \left (d x + c\right )^{2} + 3 \, {\left (163 \, A + 176 \, C\right )} a^{2} \cos \left (d x + c\right )\right )} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{384 \, {\left (d \cos \left (d x + c\right ) + d\right )}}, -\frac {3 \, {\left ({\left (163 \, A + 304 \, C\right )} a^{2} \cos \left (d x + c\right ) + {\left (163 \, A + 304 \, C\right )} a^{2}\right )} \sqrt {a} \arctan \left (\frac {\sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{\sqrt {a} \sin \left (d x + c\right )}\right ) - {\left (48 \, A a^{2} \cos \left (d x + c\right )^{4} + 184 \, A a^{2} \cos \left (d x + c\right )^{3} + 2 \, {\left (163 \, A + 48 \, C\right )} a^{2} \cos \left (d x + c\right )^{2} + 3 \, {\left (163 \, A + 176 \, C\right )} a^{2} \cos \left (d x + c\right )\right )} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{192 \, {\left (d \cos \left (d x + c\right ) + d\right )}}\right ] \]
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Timed out. \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Timed out} \]
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Timed out. \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Timed out} \]
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\[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\int { {\left (C \sec \left (d x + c\right )^{2} + A\right )} {\left (a \sec \left (d x + c\right ) + a\right )}^{\frac {5}{2}} \cos \left (d x + c\right )^{4} \,d x } \]
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Timed out. \[ \int \cos ^4(c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\int {\cos \left (c+d\,x\right )}^4\,\left (A+\frac {C}{{\cos \left (c+d\,x\right )}^2}\right )\,{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^{5/2} \,d x \]
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